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Figure 12 shows a graph of current against potential difference for an electrical component - Edexcel - GCSE Physics - Question 6 - 2018 - Paper 1

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Figure 12 shows a graph of current against potential difference for an electrical component. Which electrical component will show this variation of current with pote... show full transcript

Worked Solution & Example Answer:Figure 12 shows a graph of current against potential difference for an electrical component - Edexcel - GCSE Physics - Question 6 - 2018 - Paper 1

Step 1

Which electrical component will show this variation of current with potential difference?

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Answer

The correct answer is D, a diode. A diode allows current to flow in one direction only and will exhibit a nonlinear relationship between current and potential difference, as shown in the graph.

Step 2

Calculate the power of the lamp.

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Answer

To calculate the power of the lamp, we use the formula:
P=IimesVP = I imes V
Substituting the values gives us:
P=0.12Aimes0.24V=0.0288WP = 0.12 A imes 0.24 V = 0.0288 W
Rounded to three significant figures, the power is approximately 0.029 W.

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