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1 The picture shows a weight lifter - Edexcel - GCSE Physics - Question 1 - 2012 - Paper 1

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1 The picture shows a weight lifter. (a) In one lift, he does 5040 J of work against gravity. (i) One lift takes 4 seconds. Complete the sentence by putting a cro... show full transcript

Worked Solution & Example Answer:1 The picture shows a weight lifter - Edexcel - GCSE Physics - Question 1 - 2012 - Paper 1

Step 1

Calculate Power in Watts

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Answer

To find the power used to lift the weight, we use the formula:

P=WtP = \frac{W}{t}

Where:

  • PP is power (in Watts)
  • WW is work done (in Joules)
  • tt is time taken (in seconds)

Substituting the given values:

P=5040 J4 s=1260 WP = \frac{5040 \text{ J}}{4 \text{ s}} = 1260 \text{ W}

Thus, the correct answer is A 1260 W.

Step 2

Calculate Height Lifted

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Answer

Using the formula for gravitational potential energy:

E=mghE = mgh

Where:

  • EE is energy (in Joules)
  • mm is mass (in kg)
  • gg is gravitational field strength (in N/kg)
  • hh is height (in meters)

We know:

  • E=5040 JE = 5040 \text{ J}
  • m=240 kgm = 240 \text{ kg}
  • g=10 N/kgg = 10 \text{ N/kg}

We need to rearrange the formula to solve for height (hh):

h=Emgh = \frac{E}{mg}

Substituting the values:

h=5040 J240 kg×10 N/kg=50402400=2.1 mh = \frac{5040 \text{ J}}{240 \text{ kg} \times 10 \text{ N/kg}} = \frac{5040}{2400} = 2.1 \text{ m}

Therefore, the height he lifts this mass is:

height = 2.1 m

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