A car is travelling along a level road. (i) Complete the sentence by putting a cross (X) in the box next to your answer. When the velocity of the car is constant, the force of friction on it is: ☐ A zero ☐ B greater than the driving force ☐ C smaller than the driving force ☐ D the same size as the driving force (ii) The car now accelerates in a straight line. Its average acceleration is 12 m/s². Calculate the increase in velocity of the car in 4.0 s.

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A car is travelling along a level road - Edexcel - GCSE Physics - Question 5 - 2013 - Paper 1

Question 5

A car is travelling along a level road. (i) Complete the sentence by putting a cross (X) in the box next to your answer. When the velocity of the car is constant, t... show full transcript

Worked Solution & Example Answer:A car is travelling along a level road - Edexcel - GCSE Physics - Question 5 - 2013 - Paper 1

Step 1

Complete the sentence

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Answer

When the velocity of the car is constant, the force of friction on it is X ☐ D, the same size as the driving force. This is because when an object moves at constant velocity, all forces acting on it, including friction, are balanced.

Step 2

Calculate the increase in velocity

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Answer

To calculate the increase in velocity, we can use the formula:

ext{Change in Velocity} = ext{Acceleration} imes ext{Time}

Substituting the known values:

ext{Change in Velocity} = 12 ext{ m/s}^2 imes 4.0 ext{ s} = 48 ext{ m/s}

Therefore, the increase in velocity of the car in 4.0 seconds is 48 m/s.

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