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Figure 19 shows two objects, E and D - Edexcel - GCSE Physics - Question 10 - 2023 - Paper 1

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Figure 19 shows two objects, E and D. E emits a sound. D detects the sound. E is moving in the direction shown by the arrow, but D is not moving. E emits a s... show full transcript

Worked Solution & Example Answer:Figure 19 shows two objects, E and D - Edexcel - GCSE Physics - Question 10 - 2023 - Paper 1

Step 1

Calculate the difference between the wavelength that E emits and the wavelength that D detects.

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Answer

The difference in wavelength can be calculated using the formula:

difference in wavelength=wavelength D measureswavelength E emitsdifference \ in \ wavelength = wavelength \ D \ measures - wavelength \ E \ emits

Substituting the values:

difference \ in \ wavelength = 1.98 \ m - 1.86 \ m = 0.12 \ m

Step 2

Calculate the velocity of E.

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Answer

Using the provided equation:

velocity of E=velocity of sound times difference in wavelengthwavelength E emitsvelocity \ of \ E = \frac{velocity \ of \ sound \ times \ difference \ in \ wavelength}{wavelength \ E \ emits}

Substituting the known values:

velocity of E=330 m/s times 0.12 m1.86 mvelocity \ of \ E = \frac{330 \ m/s \ times \ 0.12 \ m}{1.86 \ m}

Calculating this gives:

velocity of E21.35 m/svelocity \ of \ E \approx 21.35 \ m/s

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