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A student uses the apparatus in Figure 3 to determine the specific heat capacity of water - Edexcel - GCSE Physics - Question 2 - 2018 - Paper 1

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A student uses the apparatus in Figure 3 to determine the specific heat capacity of water. (i) State the measurements needed to calculate the specific heat capacity... show full transcript

Worked Solution & Example Answer:A student uses the apparatus in Figure 3 to determine the specific heat capacity of water - Edexcel - GCSE Physics - Question 2 - 2018 - Paper 1

Step 1

State the measurements needed to calculate the specific heat capacity of water.

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Answer

To calculate the specific heat capacity of water, the following measurements are necessary:

  1. Mass of water - This determines the amount of substance being heated.
  2. Temperature change - The initial and final temperatures of the water must be measured to find the difference.
  3. Energy supplied - The total energy supplied to the water, as measured by the joulemeter, is essential to calculate the heat capacity.

Step 2

State two ways that the apparatus could be adapted to improve the procedure.

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Answer

  1. Add a lid or cover - This would reduce heat loss to the environment and maintain a more consistent temperature.
  2. Use insulation or lagging - Insulating the polystyrene cup can minimize heat exchange with the surroundings, improving measurement accuracy.

Step 3

Predict the temperature of the water if the heating continues up to 8 minutes.

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Answer

Based on the trend observed in the graph, one can estimate that the temperature of the water after 8 minutes would be approximately 100 °C.

Step 4

Calculate the thermal energy needed to melt the ice.

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Answer

To calculate the thermal energy required to melt the ice, we use the formula: Q=mimesLQ = m imes L where:
m = 0.38 ext{ kg (mass of ice)}
L = 3.34 imes 10^5 ext{ J/kg (latent heat of fusion of ice)}
Thus, substituting in the values: Q=0.38imes3.34imes105extJ=127,000extJ=1.27imes105extJQ = 0.38 imes 3.34 imes 10^5 ext{ J} = 127,000 ext{ J} = 1.27 imes 10^5 ext{ J} Therefore, the thermal energy needed to melt the ice is 1.27 × 10⁵ J.

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