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The students took five results for the left hand and five results for the right hand - Edexcel - GCSE Physics - Question 6 - 2016 - Paper 1

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The students took five results for the left hand and five results for the right hand. Figure 5 shows their results. which hand the distance dropped (cm) rial 1 tri... show full transcript

Worked Solution & Example Answer:The students took five results for the left hand and five results for the right hand - Edexcel - GCSE Physics - Question 6 - 2016 - Paper 1

Step 1

Calculate the average distance dropped for the right hand.

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Answer

To find the average distance dropped for the right hand, sum the distances for all trials and then divide by the number of trials:

distance dropped for right hand = 17.5 + 16.1 + 19.4 + 18.6 + 20.2 = 91.8 cm

Calculating the average:

ext{Average} = rac{91.8 ext{ cm}}{5} = 18.36 ext{ cm}

Rounding to two significant figures gives an average distance of 18 cm.

Step 2

Calculate the average time for the left hand.

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Answer

Using the equation provided, we need to fill in the distance with the average distance dropped for the left hand:

The average distance for the left hand is given as 14 cm (as shown in the table).

To find the time, we rearrange the equation:

exttime2=extdistance ext{time}^2 = ext{distance}

Thus,

ext{time} = rac{ ext{distance}}{g} where gg is the acceleration due to gravity. Assuming gextisapproximately9.8extm/s2g ext{ is approximately } 9.8 ext{ m/s}^2, we can find:

distance = 14 cm = 0.14 m

Now calculating:

ext{time} = rac{0.14 ext{ m}}{9.8 ext{ m/s}^2} = 0.0143 ext{ seconds}

Therefore, the average time for the left hand is approximately 0.014 seconds.

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