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Parents Pricing Home GCSE Edexcel Physics Stopping safely The Highway Code gives this information about the stopping distance of a car
The Highway Code gives this information about the stopping distance of a car - Edexcel - GCSE Physics - Question 1 - 2012 - Paper 1 Question 1
View full question The Highway Code gives this information about the stopping distance of a car.
speed = 30 miles per hour
thinking distance = 9 m
braking distance = 14 m
a) (i) Wha... show full transcript
View marking scheme Worked Solution & Example Answer:The Highway Code gives this information about the stopping distance of a car - Edexcel - GCSE Physics - Question 1 - 2012 - Paper 1
What is the stopping distance? Only available for registered users.
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The stopping distance is the total distance a vehicle travels while a driver reacts and then applies the brakes. It is the sum of the thinking distance and the braking distance. Given:
Thinking distance = 9 m
Braking distance = 14 m
Thus, the stopping distance can be calculated as:
e x t S t o p p i n g D i s t a n c e = e x t T h i n k i n g D i s t a n c e + e x t B r a k i n g D i s t a n c e = 9 e x t m + 14 e x t m = 23 e x t m ext{Stopping Distance} = ext{Thinking Distance} + ext{Braking Distance} = 9 ext{ m} + 14 ext{ m} = 23 ext{ m} e x t St o pp in g D i s t an ce = e x t T hinkin g D i s t an ce + e x t B r akin g D i s t an ce = 9 e x t m + 14 e x t m = 23 e x t m
Therefore, the correct option is D 23 m.
Complete the sentence Only available for registered users.
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The driver’s thinking distance is most likely to increase when:
A (the driver is tired) – Correct, because tiredness can impair reaction time.
B (there is ice on the road) – Incorrect, as this affects braking distance, not thinking distance.
C (the car is heavier) – Incorrect, as this is not a direct factor affecting thinking distance.
D (the car moves at a slower speed) – Incorrect, as slower speeds generally reduce thinking distance.
Thus, the correct option is A.
Calculate the momentum of the car. Only available for registered users.
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Momentum is defined as the product of mass and velocity. It can be calculated using the formula:
e x t M o m e n t u m = e x t M a s s i m e s e x t V e l o c i t y ext{Momentum} = ext{Mass} imes ext{Velocity} e x t M o m e n t u m = e x t M a ss im ese x t V e l oc i t y
Given:
Mass = 800 kg
Velocity = 3.0 m/s
So,
e x t M o m e n t u m = 800 e x t k g i m e s 3.0 e x t m / s = 2400 e x t k g m / s ext{Momentum} = 800 ext{ kg} imes 3.0 ext{ m/s} = 2400 ext{ kg m/s} e x t M o m e n t u m = 800 e x t k g im es 3.0 e x t m / s = 2400 e x t k g m / s
Calculate the work done by the braking force. Only available for registered users.
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Work done by a force is calculated using the formula:
e x t W o r k = e x t F o r c e i m e s e x t D i s t a n c e ext{Work} = ext{Force} imes ext{Distance} e x t W or k = e x t F orce im ese x t D i s t an ce
Given:
Force = 600 N
Distance = 15 m
Thus,
e x t W o r k = 600 e x t N i m e s 15 e x t m = 9000 e x t J ext{Work} = 600 ext{ N} imes 15 ext{ m} = 9000 ext{ J} e x t W or k = 600 e x t N im es 15 e x t m = 9000 e x t J
Complete the sentence about work done by the brakes Only available for registered users.
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The work done by the brakes during braking is equal to:
A (the energy transferred) – Correct, as work done is a measure of energy transfer.
B (the stopping distance) – Incorrect; it relates but is not equal.
C (the acceleration) – Incorrect; acceleration is not directly related.
D (the thinking distance plus braking distance) – Incorrect; this sums distances, not work done.
Thus, the correct option is A.
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