9 (a) Which of these is a vector?
A energy
B force
C mass
D work
(b) (i) State the equation that relates acceleration to change in velocity and time taken - Edexcel - GCSE Physics - Question 9 - 2020 - Paper 1
Question 9
9 (a) Which of these is a vector?
A energy
B force
C mass
D work
(b) (i) State the equation that relates acceleration to change in velocity and time t... show full transcript
Worked Solution & Example Answer:9 (a) Which of these is a vector?
A energy
B force
C mass
D work
(b) (i) State the equation that relates acceleration to change in velocity and time taken - Edexcel - GCSE Physics - Question 9 - 2020 - Paper 1
Step 1
Which of these is a vector?
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Answer
The vector among the given options is B: force. A vector is a quantity that has both magnitude and direction, and force fits this definition.
Step 2
State the equation that relates acceleration to change in velocity and time taken.
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Answer
The equation that relates acceleration (a) to change in velocity (Δv) and time taken (t) is given by:
a=tΔv
where Δv is the change in velocity, calculated as the final velocity minus the initial velocity.
Step 3
Calculate the acceleration of the van.
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Answer
To calculate the acceleration of the van, we can use the formula:
a=tΔv
Where:
Initial velocity, vi=2 m/s
Final velocity, vf=20 m/s
Time, t=12 s
Calculating Δv:
Δv=vf−vi=20−2=18 m/s
Now, substituting into the equation:
a=12 s18 m/s=1.5 m/s2.
Therefore, the acceleration of the van is 1.5 m/s².
Step 4
Calculate the distance the cyclist travels in the 15s.
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Answer
To calculate the distance traveled by the cyclist, we can find the area under the velocity-time graph. The graph forms a right triangle with:
Base (time) = 15 s
Height (velocity) = 7 m/s.
The formula for the area of a triangle is:
extArea=21×base×height
Calculating the area:
extArea=21×15 s×7 m/s=2105=52.5 m.
Thus, the distance the cyclist travels in 15 seconds is 52.5 m.
Step 5
Explain how the stopping distance of a car is affected by factors involving the driver.
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Answer
The stopping distance of a car can be significantly affected by several factors involving the driver:
Reaction Time: A driver's reaction time (the time taken to respond to a hazard) can vary. A delayed reaction can increase the stopping distance.
Tiredness: A tired driver may have slower reflexes, which can also delay their reaction time.
Effect of Drugs: Use of drugs (both illegal and certain legal medications) can impair judgment and slow reaction times.
Footwear: Inappropriate footwear can impede a driver's ability to operate the pedals effectively, potentially resulting in longer stopping distances.
These factors lead to an increased overall stopping distance due to either increased thinking/braking distance.
Step 6
Explain how the stopping distance of a car is affected by factors involving the car or the road.
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Answer
The stopping distance of a car is influenced by several factors related to either the car itself or the road conditions:
Mass/Weight of the Car: Heavier vehicles require more distance to stop compared to lighter vehicles due to the greater inertia.
State of Brakes: Worn or poorly maintained brakes can significantly affect stopping efficiency, increasing stopping distance.
Tire Condition: Tires with insufficient tread or improper inflation can reduce grip, meaning the car takes longer to stop.
State of the Road: Wet, icy, or poorly maintained roads can create hazardous conditions, increasing stopping distance due to reduced traction.
In summary, both driver behavior and vehicle/road conditions play crucial roles in determining stopping distance.