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Figure 19 shows two objects, E and D - Edexcel - GCSE Physics - Question 10 - 2023 - Paper 1

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Figure 19 shows two objects, E and D. E emits a sound. D detects the sound. E is moving in the direction shown by the arrow, but D is not moving. E emits a sound... show full transcript

Worked Solution & Example Answer:Figure 19 shows two objects, E and D - Edexcel - GCSE Physics - Question 10 - 2023 - Paper 1

Step 1

Calculate the difference between the wavelength that E emits and the wavelength that D detects.

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Answer

To find the difference in wavelength, we need to subtract the wavelength emitted by E from the wavelength detected by D.

Given:

  • Wavelength emitted by E = 1.86 m
  • Wavelength detected by D = 1.98 m

The calculation is:

extDifferenceinwavelength=1.98extm1.86extm=0.12extm ext{Difference in wavelength} = 1.98 ext{ m} - 1.86 ext{ m} = 0.12 ext{ m}

Step 2

Calculate the velocity of E.

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Answer

We use the provided equation to find the velocity of E:

ext{velocity of E} = rac{ ext{velocity of sound} imes ext{difference in wavelength}}{ ext{wavelength E emits}}

Substituting the known values:

  • Velocity of sound = 330 m/s
  • Difference in wavelength = 0.12 m
  • Wavelength emitted by E = 1.86 m

The calculation becomes:

ext{velocity of E} = rac{330 ext{ m/s} imes 0.12 ext{ m}}{1.86 ext{ m}} \ ext{velocity of E} = rac{39.6}{1.86} \ ext{velocity of E} ext{ ≈ } 21.24 ext{ m/s}

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