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The picture shows a weight lifter - Edexcel - GCSE Physics - Question 1 - 2012 - Paper 1

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Question 1

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The picture shows a weight lifter. (a) In one lift, he does 5040 J of work against gravity. (i) One lift takes 4 seconds. Complete the sentence by putting a cross ... show full transcript

Worked Solution & Example Answer:The picture shows a weight lifter - Edexcel - GCSE Physics - Question 1 - 2012 - Paper 1

Step 1

Calculate Power

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Answer

Power can be calculated using the formula:

P=WtP = \frac{W}{t}

where:

  • W is the work done (5040 J)
  • t is the time taken (4 s)

Substituting the known values:

P=5040 J4 s=1260 WP = \frac{5040 \text{ J}}{4 \text{ s}} = 1260 \text{ W}

Thus, the correct option is A 1260 W.

Step 2

Calculate Height Lifted

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Answer

To calculate the height lifted, we can use the relationship between work, force, and height:

W=FhW = F \cdot h

Where:

  • W is the work done (5040 J)
  • F is the force, which is equal to the weight of the mass lifted. The weight can be calculated as:
F=mgF = m \cdot g

with:

  • m = 240 kg (mass)
  • g = 10 N/kg (gravitational field strength)

Calculating the weight:

F=240 kg10 N/kg=2400 NF = 240 \text{ kg} \cdot 10 \text{ N/kg} = 2400 \text{ N}

Now substituting F back into the work formula:

5040=2400h5040 = 2400 \cdot h

Solving for h:

h=50402400=2.1 mh = \frac{5040}{2400} = 2.1 \text{ m}

Thus, the height he lifts this mass is 2.1 m.

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