Photo AI

A radio transfers 30 J of potential energy to 27 J of useful energy - OCR Gateway - GCSE Physics - Question 14 - 2021 - Paper 2

Question 14

A radio transfers 30 J of potential energy to 27 J of useful energy. What is the efficiency and energy loss for the radio? | Efficiency | Energy loss | |----------... show full transcript

Worked Solution & Example Answer:A radio transfers 30 J of potential energy to 27 J of useful energy - OCR Gateway - GCSE Physics - Question 14 - 2021 - Paper 2

Step 1

Calculate Efficiency

96%

114 rated

Answer

The efficiency of a device is calculated using the formula:

$\text{Efficiency} = \frac{\text{Useful Energy}}{\text{Total Energy}} \times 100 \%$

Substituting the values, we have:

$\text{Efficiency} = \frac{27 \text{ J}}{30 \text{ J}} \times 100 \% = 90\%$

Step 2

Calculate Energy Loss

99%

104 rated

Answer

Energy loss can be calculated as:

$\text{Energy Loss} = \text{Total Energy} - \text{Useful Energy}$

Substituting the values, we find:

$\text{Energy Loss} = 30 \text{ J} - 27 \text{ J} = 3 \text{ J}$

Step 3

Final Answer

96%

101 rated

Answer

From the calculations, the efficiency is 90% and the energy loss is 3 J. Therefore, the correct option is C.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;