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A spring stretches by 2.0cm when a force is added - OCR Gateway - GCSE Physics - Question 15 - 2019 - Paper 3

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A spring stretches by 2.0cm when a force is added. The spring constant is 60N/m. Calculate the energy transferred to the spring when it is stretched. A B C D You... show full transcript

Worked Solution & Example Answer:A spring stretches by 2.0cm when a force is added - OCR Gateway - GCSE Physics - Question 15 - 2019 - Paper 3

Step 1

Calculate the energy transferred to the spring when it is stretched.

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Answer

To calculate the energy transferred to the spring, we use the formula for elastic potential energy:

E=12kx2E = \frac{1}{2} k x^2

where:

  • EE is the energy in joules (J)
  • kk is the spring constant (60 N/m)
  • xx is the extension of the spring in meters (2.0 cm = 0.02 m)

Now, substituting the given values:

  1. Convert the extension to meters: x=2.0cm=0.02mx = 2.0 \, \text{cm} = 0.02 \, \text{m}

  2. Substitute into the energy formula: E=12×60N/m×(0.02m)2E = \frac{1}{2} \times 60 \, \text{N/m} \times (0.02 \, \text{m})^2

  3. Calculate: E=12×60×0.0004E = \frac{1}{2} \times 60 \times 0.0004 E=0.012JE = 0.012 \, \text{J}

Thus, the energy transferred to the spring when it is stretched is 0.012 J.

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