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Alvin has a crate in the shape of a cuboid - OCR - GCSE Maths - Question 18 - 2017 - Paper 1

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Alvin has a crate in the shape of a cuboid. The crate is open at the top. The internal dimensions of the crate are 46 cm long by 46 cm wide by 55 cm high. Alvin has... show full transcript

Worked Solution & Example Answer:Alvin has a crate in the shape of a cuboid - OCR - GCSE Maths - Question 18 - 2017 - Paper 1

Step 1

Calculate the length of the stick that extends out of the crate.

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Answer

To find the length of the stick that extends out of the crate, we need to determine how much of the stick is inside the crate.

The height of the crate is 55 cm, and the total length of the stick is 95 cm.

The length that extends out can be calculated as follows:

lengthextout=totalextlengthheightextofcratelength ext{ out} = total ext{ length} - height ext{ of crate}

Substituting the values:

lengthextout=95extcm55extcmlength ext{ out} = 95 ext{ cm} - 55 ext{ cm}

lengthextout=40extcmlength ext{ out} = 40 ext{ cm}

Thus, the length of the stick that extends out of the crate is 40 cm.

Step 2

Calculate the angle the stick makes with the base of the crate.

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Answer

To find the angle that the stick makes with the base of the crate, we can use trigonometry. Specifically, we will use the tangent function:

Given that the length of the stick above the crate is 40 cm (from part (a)) and the height of the crate is 55 cm, we can use the following relationship:

tan(heta)=oppositeadjacenttan( heta) = \frac{opposite}{adjacent}

Here, the "opposite" side is the height of the crate (55 cm), and the "adjacent" side is the length of the stick above the crate (40 cm). Therefore:

tan(heta)=5540tan( heta) = \frac{55}{40}

To find the angle, we take the arctangent (inverse tangent):

θ=arctan(5540)\theta = arctan\left(\frac{55}{40}\right)

Calculating this gives:

θ40.2°\theta \approx 40.2°

Thus, the angle the stick makes with the base of the crate is approximately 40.2°.

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