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A, B, C and D are four towns - OCR - GCSE Maths - Question 7 - 2017 - Paper 1

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A, B, C and D are four towns. B is 25 kilometres due East of A. C is 25 kilometres due North of A. D is 45 kilometres due South of A. (a) Work out the bearing of B ... show full transcript

Worked Solution & Example Answer:A, B, C and D are four towns - OCR - GCSE Maths - Question 7 - 2017 - Paper 1

Step 1

Work out the bearing of B from C.

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Answer

To find the bearing of B from C, we first need to determine the position of A relative to C and B.

  1. Positioning:

    • A is the reference point at (0, 0).
    • B is at (25, 0).
    • C is at (0, 25).
  2. Finding Coordinates:

    • C to A: moves 25 km South to reach point A.
    • B is 25 km East of A.
  3. Calculating the angle:

    • Draw a line from C to B.
    • The angle at point A formed by the North (vertical line) and line CB can be found using the tangent function: tan(θ)=oppositeadjacent=2525=1\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{25}{25} = 1
    • Thus, ( \theta = 45^{\circ} ).
  4. Finding the Bearing:

    • Bearings are measured clockwise from North. Therefore, the bearing of B from C is: 90+45=135.90^{\circ} + 45^{\circ} = 135^{\circ}.

Step 2

Calculate the bearing of D from B.

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Answer

To determine the bearing of D from B, we need to establish the coordinates of D:

  1. Positioning:

    • D is 45 km South of A, making its coordinates (0, -45).
    • B is at (25, 0).
  2. Drawing a Triangle:

    • From B, draw a line to D.
    • You will create a right triangle, with A as a common point.
  3. Calculating the Angle at A:

    • The angle at A (angle DAB) can be found using the tangent function:
      • The vertical distance from A to D is 45 km, and from A to B is 25 km.
      • The angle can be found using: tan(ϕ)=4525ϕ=tan1(1.8).\tan(\phi) = \frac{45}{25} \Rightarrow \phi = \tan^{-1}(1.8).
  4. Calculating the Bearing:

    • Calculate ( \phi ) and add it to the 270° bearing from North (South direction): Bearing of D from B=270+ϕ\text{Bearing of D from B} = 270^{\circ} + \phi
    • This gives us a bearing of approximately 209° to 209.1°.

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