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7(a) Simplify - OCR - GCSE Maths - Question 7 - 2017 - Paper 1

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7(a) Simplify. 7l - 6u + 5t - 4u (b) Factorise. 5v + 20w (c) Solve by factorising. x² + 10x + 21 = 0

Worked Solution & Example Answer:7(a) Simplify - OCR - GCSE Maths - Question 7 - 2017 - Paper 1

Step 1

Simplify.

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Answer

To simplify the expression 7l6u+5t4u7l - 6u + 5t - 4u, first combine like terms. The like terms in this expression are those containing uu:

7l+(6u4u)+5t=7l10u+5t7l + ( -6u - 4u) + 5t = 7l - 10u + 5t

Thus, the simplified expression is:

7l10u+5t7l - 10u + 5t

Step 2

Factorise.

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Answer

To factorise the expression 5v+20w5v + 20w, we look for the greatest common factor (GCF).

The GCF of 5v5v and 20w20w is 55. Therefore, the factorised form is:

5(v+4w)5(v + 4w)

Step 3

Solve by factorising.

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Answer

To solve the quadratic equation x2+10x+21=0x² + 10x + 21 = 0 by factorising, we need to express it in the form of (x+a)(x+b)=0(x + a)(x + b) = 0, where ab=21ab = 21 and a+b=10a + b = 10. The pairs of factors of 2121 are (1,21)(1, 21) and (3,7)(3, 7). The correct pair that adds up to 1010 is (3,7)(3, 7):

x2+10x+21=(x+3)(x+7)=0x² + 10x + 21 = (x + 3)(x + 7) = 0

Setting each factor to zero gives:

x+3=0extorx+7=0x + 3 = 0 ext{ or } x + 7 = 0

Thus, the solutions are:

x=3extorx=7x = -3 ext{ or } x = -7

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