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Parents Pricing Home GCSE OCR Maths 3D trigonometry The diagram represents a rectangular garden of length 10m and width 8m
The diagram represents a rectangular garden of length 10m and width 8m - OCR - GCSE Maths - Question 10 - 2017 - Paper 1 Question 10
View full question The diagram represents a rectangular garden of length 10m and width 8m.
The flower bed is a triangle and the patio is a trapezium.
The rest of the garden is lawn.
W... show full transcript
View marking scheme Worked Solution & Example Answer:The diagram represents a rectangular garden of length 10m and width 8m - OCR - GCSE Maths - Question 10 - 2017 - Paper 1
Calculate the area of the entire garden Only available for registered users.
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The area of the rectangular garden can be calculated using the formula:
e x t A r e a = e x t l e n g t h i m e s e x t w i d t h = 10 e x t m i m e s 8 e x t m = 80 e x t m 2 ext{Area} = ext{length} imes ext{width} = 10 ext{m} imes 8 ext{m} = 80 ext{m}^2 e x t A re a = e x t l e n g t h im ese x t w i d t h = 10 e x t m im es 8 e x t m = 80 e x t m 2
Calculate the area of the flower bed Only available for registered users.
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The flower bed is a triangle with a base of 2m and a height of 6m. The area of a triangle is calculated using:
e x t A r e a = 1 2 × e x t b a s e × e x t h e i g h t = 1 2 × 2 e x t m × 6 e x t m = 6 e x t m 2 ext{Area} = \frac{1}{2} \times ext{base} \times ext{height} = \frac{1}{2} \times 2 ext{m} \times 6 ext{m} = 6 ext{m}^2 e x t A re a = 2 1 × e x t ba se × e x t h e i g h t = 2 1 × 2 e x t m × 6 e x t m = 6 e x t m 2
Calculate the area of the patio Only available for registered users.
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The patio is a trapezium with bases of 5m and 8m, and a height of 3m. The area of a trapezium is calculated using:
e x t A r e a = 1 2 × ( b 1 + b 2 ) × h = 1 2 × ( 5 e x t m + 8 e x t m ) × 3 e x t m = 1 2 × 13 e x t m × 3 e x t m = 19.5 e x t m 2 ext{Area} = \frac{1}{2} \times (b_1 + b_2) \times h = \frac{1}{2} \times (5 ext{m} + 8 ext{m}) \times 3 ext{m} = \frac{1}{2} \times 13 ext{m} \times 3 ext{m} = 19.5 ext{m}^2 e x t A re a = 2 1 × ( b 1 + b 2 ) × h = 2 1 × ( 5 e x t m + 8 e x t m ) × 3 e x t m = 2 1 × 13 e x t m × 3 e x t m = 19.5 e x t m 2
Calculate the area of the lawn Only available for registered users.
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To find the area of the lawn, we subtract the areas of the flower bed and the patio from the area of the entire garden:
e x t A r e a o f l a w n = e x t A r e a o f g a r d e n − ( e x t A r e a o f f l o w e r b e d + e x t A r e a o f p a t i o ) ext{Area of lawn} = ext{Area of garden} - ( ext{Area of flower bed} + ext{Area of patio}) e x t A re a o f l a w n = e x t A re a o f g a r d e n − ( e x t A re a o ff l o w er b e d + e x t A re a o f p a t i o )
Calculating this gives:
e x t A r e a o f l a w n = 80 e x t m 2 − ( 6 e x t m 2 + 19.5 e x t m 2 ) = 80 e x t m 2 − 25.5 e x t m 2 = 54.5 e x t m 2 ext{Area of lawn} = 80 ext{m}^2 - (6 ext{m}^2 + 19.5 ext{m}^2) = 80 ext{m}^2 - 25.5 ext{m}^2 = 54.5 ext{m}^2 e x t A re a o f l a w n = 80 e x t m 2 − ( 6 e x t m 2 + 19.5 e x t m 2 ) = 80 e x t m 2 − 25.5 e x t m 2 = 54.5 e x t m 2 Join the GCSE students using SimpleStudy...97% of StudentsReport Improved Results
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