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The design below is made from two sectors of circles, centre O: Calculate the perimeter of the shaded part - OCR - GCSE Maths - Question 8 - 2017 - Paper 1

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The design below is made from two sectors of circles, centre O: Calculate the perimeter of the shaded part. Give your answer correct to 3 significant figures.

Worked Solution & Example Answer:The design below is made from two sectors of circles, centre O: Calculate the perimeter of the shaded part - OCR - GCSE Maths - Question 8 - 2017 - Paper 1

Step 1

Calculate the perimeter of the first sector with radius 6 cm and angle 45°

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Answer

To find the length of the arc for the first sector, we use the formula:

ArcLength=θ360×2πrArcLength = \frac{\theta}{360} \times 2 \pi r

Here, ( \theta = 45° ) and ( r = 6 ) cm.

So,

ArcLength=45360×2π×6=18×12π=1.5π4.71 cmArcLength = \frac{45}{360} \times 2 \pi \times 6 = \frac{1}{8} \times 12\pi = 1.5\pi \approx 4.71 \text{ cm}

Step 2

Calculate the perimeter of the second sector with radius 3.5 cm and angle 45°

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Answer

Using the same formula for the second sector with radius 3.5 cm:

ArcLength=45360×2πrArcLength = \frac{45}{360} \times 2 \pi r

Here, ( r = 3.5 ) cm:

ArcLength=45360×2π×3.5=18×7π=0.875π2.75 cmArcLength = \frac{45}{360} \times 2 \pi \times 3.5 = \frac{1}{8} \times 7\pi = 0.875\pi \approx 2.75 \text{ cm}

Step 3

Add the straight edges of the sectors

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Answer

The straight edges of the sectors are the two radii, one of length 6 cm and one of length 3.5 cm:

TotalStraightEdges=6+3.5=9.5 cmTotalStraightEdges = 6 + 3.5 = 9.5\text{ cm}

Step 4

Calculate the total perimeter of the shaded part

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Answer

Now, we sum the lengths of the arc and the straight edges:

TotalPerimeter=ArcLength1+ArcLength2+TotalStraightEdgesTotalPerimeter = ArcLength_1 + ArcLength_2 + TotalStraightEdges

Substituting the values we calculated:

TotalPerimeter4.71+2.75+9.5=16.96 cmTotalPerimeter \approx 4.71 + 2.75 + 9.5 = 16.96 \text{ cm}

Rounding to three significant figures gives:

TotalPerimeter17.0 cmTotalPerimeter \approx 17.0 \text{ cm}

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