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The diagram shows a pyramid ABCDE - OCR - GCSE Maths - Question 17 - 2021 - Paper 1

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The diagram shows a pyramid ABCDE. The pyramid has a square horizontal base ABCD with side 5.6cm. The vertex E is vertically above the centre O of the base. The he... show full transcript

Worked Solution & Example Answer:The diagram shows a pyramid ABCDE - OCR - GCSE Maths - Question 17 - 2021 - Paper 1

Step 1

Calculate the Area of the Base (ABCD)

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Answer

The base ABCD is a square with side length 5.6 cm.

The area of the base can be calculated as:

extAreaextbase=extside2=5.62=31.36extcm2 ext{Area}_{ ext{base}} = ext{side}^2 = 5.6^2 = 31.36 ext{ cm}^2

Step 2

Calculate the Slant Height (ED)

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Answer

To find the slant height ED, we can use the Pythagorean theorem in triangle OED.

We know that:

  • OE = 6.8 cm (height of the pyramid)
  • OD = \frac{5.6}{2} = 2.8 cm (half the length of the base)

Using the Pythagorean theorem:

ED=OE2+OD2=6.82+2.82ED = \sqrt{OE^2 + OD^2} = \sqrt{6.8^2 + 2.8^2}

Calculating those values:

=46.24+7.84=54.08≈7.35extcm= \sqrt{46.24 + 7.84} = \sqrt{54.08} \approx 7.35 ext{ cm}

Step 3

Calculate the Area of One Triangular Face (ABE)

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Answer

The area of one triangular face (e.g., ABE) can be calculated using the formula:

extAreaexttriangle=12×extbase×extheight ext{Area}_{ ext{triangle}} = \frac{1}{2} \times ext{base} \times ext{height}

The base AB = 5.6 cm and height (slant height) ED = 7.35 cm:

extAreaextABE=12×5.6×7.35≈20.52extcm2 ext{Area}_{ ext{ABE}} = \frac{1}{2} \times 5.6 \times 7.35 \approx 20.52 ext{ cm}^2

Step 4

Calculate the Total Lateral Surface Area

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Answer

Since there are 4 triangular faces, the total lateral surface area can be calculated as:

extTotallateral=4×extAreaexttriangle≈4×20.52≈82.08extcm2 ext{Total_{lateral}} = 4 \times ext{Area}_{ ext{triangle}} \approx 4 \times 20.52 \approx 82.08 ext{ cm}^2

Step 5

Calculate the Total Surface Area of the Pyramid

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Answer

Finally, the total surface area of the pyramid is the sum of the base area and the total lateral surface area:

extTotalsurface=extAreaextbase+extTotallateral ext{Total_{surface}} = ext{Area}_{ ext{base}} + ext{Total_{lateral}}

Substituting the values:

=31.36+82.08≈113.44extcm2= 31.36 + 82.08 \approx 113.44 ext{ cm}^2

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