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The diagram shows a quadrilateral, PQRS - OCR - GCSE Maths - Question 11 - 2023 - Paper 6

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Question 11

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The diagram shows a quadrilateral, PQRS. PS = 10 cm. Angle QPS = Angle PSR = 90°. SR is 6 cm longer than PQ. The area of quadrilateral PQRS is A cm². Write a simpl... show full transcript

Worked Solution & Example Answer:The diagram shows a quadrilateral, PQRS - OCR - GCSE Maths - Question 11 - 2023 - Paper 6

Step 1

Determine Lengths Using Given Information

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Answer

Let PQ = x cm. Then, since SR is 6 cm longer than PQ, we have SR = x + 6 cm.

The height of the quadrilateral, taken from point R to side PS (which is the base), is the height PS = 10 cm.

Step 2

Calculate the Area of Quadrilateral PQRS

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Answer

The area of a trapezoid can be calculated using the formula:

Area=(b1+b2)×h2Area = \frac{(b_1 + b_2) \times h}{2}

Here, b1 = PQ = x cm, b2 = SR = x + 6 cm, and h = 10 cm.

Thus, we have:

A=(x+(x+6))×102A = \frac{(x + (x + 6)) \times 10}{2}

Simplifying this gives:

A=(2x+6)×102=(2x+6)×5=10x+30A = \frac{(2x + 6) \times 10}{2} = (2x + 6) \times 5 = 10x + 30

Step 3

Solve for PQ in Terms of A

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Answer

Rearranging the area equation:

10x+30=A10x + 30 = A

Then, isolate x:

10x=A3010x = A - 30

And finally, divide by 10:

PQ=x=A3010PQ = x = \frac{A - 30}{10}

Thus, we have the expression for PQ in terms of A as:

PQ=A3010PQ = \frac{A - 30}{10}

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