The diagram shows a quadrilateral, PQRS - OCR - GCSE Maths - Question 11 - 2023 - Paper 6
Question 11
The diagram shows a quadrilateral, PQRS.
PS = 10 cm.
Angle QPS = Angle PSR = 90°.
SR is 6 cm longer than PQ.
The area of quadrilateral PQRS is A cm².
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Worked Solution & Example Answer:The diagram shows a quadrilateral, PQRS - OCR - GCSE Maths - Question 11 - 2023 - Paper 6
Step 1
Determine Lengths Using Given Information
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Answer
Let PQ = x cm. Then, since SR is 6 cm longer than PQ, we have SR = x + 6 cm.
The height of the quadrilateral, taken from point R to side PS (which is the base), is the height PS = 10 cm.
Step 2
Calculate the Area of Quadrilateral PQRS
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Answer
The area of a trapezoid can be calculated using the formula:
Area=2(b1+b2)×h
Here, b1 = PQ = x cm, b2 = SR = x + 6 cm, and h = 10 cm.
Thus, we have:
A=2(x+(x+6))×10
Simplifying this gives:
A=2(2x+6)×10=(2x+6)×5=10x+30
Step 3
Solve for PQ in Terms of A
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Answer
Rearranging the area equation:
10x+30=A
Then, isolate x:
10x=A−30
And finally, divide by 10:
PQ=x=10A−30
Thus, we have the expression for PQ in terms of A as: