The area of a rectangle is 56 m², correct to the nearest m² - OCR - GCSE Maths - Question 11 - 2019 - Paper 4

The length is given as 9.2 m, correct to the nearest 0.1 m. This means the length can range from 9.15 m to 9.25 m.

Using the maximum area of 56.5 m² and the minimum length of 9.15 m, we can calculate width using the formula:

$ext{Width} = \frac{\text{Area}}{\text{Length}}$

Substituting the values, we have:

$\text{Width} = \frac{56.5}{9.25} \approx 6.1 \text{ m}$

Since the width needs to be the smallest possible value meeting the area constraint, we can also calculate using the maximum length:

$\text{Width} = \frac{56.5}{9.15} \approx 6.2 \text{ m}$ Therefore, the smallest possible width is calculated using the minimum length for the maximum area, giving us:

$\text{Answer: } 6.1 \text{ m}$