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A square is divided into three rectangles, A, B and C - OCR - GCSE Maths - Question 10 - 2017 - Paper 1

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A square is divided into three rectangles, A, B and C. Rectangle A has length n cm and a width of 2 cm. Rectangle C has length 4 cm. (a) (i) Write down an algebr... show full transcript

Worked Solution & Example Answer:A square is divided into three rectangles, A, B and C - OCR - GCSE Maths - Question 10 - 2017 - Paper 1

Step 1

Write down an algebraic expression for the width of rectangle C.

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Answer

Since the total width of the square is 4 cm and rectangle A has a width of 2 cm, the width of rectangle C can be calculated as:

extWidthofrectangleC=4n ext{Width of rectangle C} = 4 - n

Step 2

Write down an algebraic expression for the area of rectangle A.

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Answer

The area of rectangle A can be calculated using the formula for the area of a rectangle, which is:

extArea=extlengthimesextwidth ext{Area} = ext{length} imes ext{width}

Therefore, the area of rectangle A is:

extAreaofrectangleA=nimes2=2nextcm2 ext{Area of rectangle A} = n imes 2 = 2n ext{ cm}^2

Step 3

Work out the value of n.

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Answer

To find the value of n, we know that all rectangles have the same area. Let's denote the area of rectangle B which has a width of (4n)(4 - n) and height of 2 cm:

extAreaofrectangleB=(4n)imes2=2(4n) ext{Area of rectangle B} = (4 - n) imes 2 = 2(4 - n)

Setting the areas equal (as all rectangles have the same area) gives us:

2n=2(4n)2n = 2(4 - n)

Dividing both sides by 2:

n=4nn = 4 - n

Rearranging the equation:

2n=42n = 4

Thus, solving for n gives:

n=2n = 2

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