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The table shows the relative frequencies of the results for a football team after a number of games - OCR - GCSE Maths - Question 18 - 2018 - Paper 1

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The table shows the relative frequencies of the results for a football team after a number of games. Result of game won lost drew Relative frequency 0.2 0.45 (a) C... show full transcript

Worked Solution & Example Answer:The table shows the relative frequencies of the results for a football team after a number of games - OCR - GCSE Maths - Question 18 - 2018 - Paper 1

Step 1

Complete the table.

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Answer

To complete the table, first, we need to find the relative frequency of the 'drew' outcomes. Since the total relative frequency must sum to 1, we can calculate it as:

extRelativefrequencyofdrew=1(extRelativefrequencyofwon+extRelativefrequencyoflost)=1(0.2+0.45)=10.65=0.35 ext{Relative frequency of drew} = 1 - ( ext{Relative frequency of won} + ext{Relative frequency of lost}) = 1 - (0.2 + 0.45) = 1 - 0.65 = 0.35

Thus, the completed relative frequencies are:

  • Won: 0.2
  • Lost: 0.45
  • Drew: 0.35

Step 2

The team lost 10 more games than they won. How many games did the team play altogether?

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Answer

Let the number of games won be denoted as xx. Since the team lost 10 more games than they won, the number of games lost will be x+10x + 10.

Using the relative frequencies:

  • The overall relative frequency of lost games is 0.45, which means:
rac{x + 10}{N} = 0.45

where NN is the total number of games played.

From part (a), we also have:

rac{x}{N} = 0.2 ext{ (for won games)}

Now substituting x=0.2Nx = 0.2N into the lost games equation:

rac{0.2N + 10}{N} = 0.45

Simplifying the equation:

0.2N+10=0.45N0.2N + 10 = 0.45N 10=0.45N0.2N10 = 0.45N - 0.2N 10=0.25N10 = 0.25N

So,

N = rac{10}{0.25} = 40

The team played a total of 40 games.

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