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The masses, mkg, of some parcels are shown below - OCR - GCSE Maths - Question 16 - 2020 - Paper 1

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The masses, mkg, of some parcels are shown below. 4 15 14 11 12 3 1 18 13 2 16 10 Jack constructs this grouped frequency table to record the masses. | ... show full transcript

Worked Solution & Example Answer:The masses, mkg, of some parcels are shown below - OCR - GCSE Maths - Question 16 - 2020 - Paper 1

Step 1

Explain why Jack's table is unsuitable to record the masses.

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Answer

Jack's table is unsuitable because the frequency intervals he has chosen overlap. The ranges '0 ≤ m < 5' and '5 ≤ m < 10' are correctly defined, but higher ranges such as '10 ≤ m < 15' and '15 ≤ m ≤ 20' create ambiguity. For instance, a mass of 15 kg could fit into both the '10 ≤ m < 15' and '15 ≤ m ≤ 20' categories, leading to confusion in data recording.

Step 2

Show that 70 students took between 45 and 50 minutes to complete the race.

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Answer

To find the total number of students between 45 and 50 minutes, we calculate the area of the bars in the histogram from 45 to 50 minutes. According to the histogram:

  • The frequency density for the interval from 45 to 50 minutes is approximately 1.5.
  • The width of this interval is 5 minutes.

Using the formula for area:

extNumberofStudents=extFrequencyDensityimesextWidth=1.5imes5=7.5 ext{Number of Students} = ext{Frequency Density} imes ext{Width} = 1.5 imes 5 = 7.5

Similarly, for the interval from 50 to 60 minutes, the frequency density is 5 with the same width:

extNumberofStudents=5imes10=50 ext{Number of Students} = 5 imes 10 = 50

Adding these gives us:

7.5+50=707.5 + 50 = 70

Thus, 70 students took between 45 and 50 minutes to complete the race.

Step 3

Calculate an estimate of the mean time taken to complete the race. Show your working.

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Answer

To calculate the mean time, we use the midpoints of each interval in conjunction with the frequency densities:

  • For 30 to 40 minutes (Frequency Density = 2), Midpoint = 35: 35imes2imes10=70035 imes 2 imes 10 = 700
  • For 40 to 50 minutes (Frequency Density = 5), Midpoint = 45: 45imes5imes10=225045 imes 5 imes 10 = 2250
  • For 50 to 60 minutes (Frequency Density = 4), Midpoint = 55: 55imes4imes10=220055 imes 4 imes 10 = 2200
  • For 60 to 70 minutes (Frequency Density = 1.5), Midpoint = 65: 65imes1.5imes10=97565 imes 1.5 imes 10 = 975

Now, we sum up all the products:

700+2250+2200+975=5815700 + 2250 + 2200 + 975 = 5815

Next, we need the total number of students, calculated earlier as 70. Thus, we compute the mean:

ext{Mean} = rac{5815}{70} = 83.0714

Hence, the estimated mean time taken to complete the race is approximately 83.07 minutes.

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