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The histogram summarises a health score for a group of people - OCR - GCSE Maths - Question 10 - 2017 - Paper 1

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The histogram summarises a health score for a group of people. (a) Estimate the fraction of the group who had a score of 45 or more. (b) What assumption did you ma... show full transcript

Worked Solution & Example Answer:The histogram summarises a health score for a group of people - OCR - GCSE Maths - Question 10 - 2017 - Paper 1

Step 1

(a) Estimate the fraction of the group who had a score of 45 or more.

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Answer

To estimate the fraction of the group who had a score of 45 or more, observe the histogram. We need to find the area of the bars corresponding to scores of 45 and above.

  1. Identify the relevant range: The scores of 45-100 correspond to the histogram bars that start at 40 and end at 100.

  2. Estimate the height of the bars: From the histogram, the height at 40-50 is approximately 0.5, and from 50-60, it is approximately 0.9, with decreasing values for the remaining intervals.

  3. Calculate the area under these bars:

    • For the 40-50 interval (height 0.5 and width 10):

      extArea=extHeight×Width=0.5×10=5 ext{Area} = ext{Height} \times \text{Width} = 0.5 \times 10 = 5

    • For the 50-60 interval (height 0.9 and width 10):

      extArea=0.9×10=9 ext{Area} = 0.9 \times 10 = 9

    • For the 60-70 interval (height 0.4 and width 10):

      extArea=0.4×10=4 ext{Area} = 0.4 \times 10 = 4

    • For the 70-80 interval (height 0.2 and width 10):

      extArea=0.2×10=2 ext{Area} = 0.2 \times 10 = 2

    • For the 80-90 interval (height 0.1 and width 10):

      extArea=0.1×10=1 ext{Area} = 0.1 \times 10 = 1

  4. Sum the areas:

    extTotalArea=5+9+4+2+1=21 ext{Total Area} = 5 + 9 + 4 + 2 + 1 = 21

  5. Estimate the total number of participants from the histogram, if treated as 100:

    extFraction=21100=0.21 ext{Fraction} = \frac{21}{100} = 0.21

Therefore, the estimated fraction of the group who had a score of 45 or more is approximately 0.21.

Step 2

(b) What assumption did you make in answering part (a)?

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Answer

In answering part (a), I assumed that the distribution of health scores represented in the histogram is uniform within each interval. This means I considered all values in a specific interval to contribute equally to the total area, without accounting for any variability that might exist within those intervals.

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