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Use the formula $s = ut + \frac{1}{2} at^2$ - OCR - GCSE Maths - Question 1 - 2017 - Paper 1

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Question 1

Use-the-formula-$s-=-ut-+-\frac{1}{2}-at^2$-OCR-GCSE Maths-Question 1-2017-Paper 1.png

Use the formula $s = ut + \frac{1}{2} at^2$. (a) Calculate $s$ when $u = 5$, $t = 10$ and $a = 3$. (b) Make $a$ the subject of the formula.

Worked Solution & Example Answer:Use the formula $s = ut + \frac{1}{2} at^2$ - OCR - GCSE Maths - Question 1 - 2017 - Paper 1

Step 1

(a) Calculate $s$ when $u = 5$, $t = 10$ and $a = 3$.

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Answer

To calculate ss, we will use the given formula:

s=ut+12at2s = ut + \frac{1}{2} at^2

Substituting the values into the formula:

s=(5)(10)+12(3)(102)s = (5)(10) + \frac{1}{2}(3)(10^2)

Calculating each term:

  • First term: 5×10=505 \times 10 = 50
  • Second term: 12×3×100=150\frac{1}{2} \times 3 \times 100 = 150

Adding both results together:

s=50+150=200s = 50 + 150 = 200

Thus, the calculated value of ss is 200200.

Step 2

(b) Make $a$ the subject of the formula.

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Answer

To make aa the subject of the formula, we start with the original equation:

s=ut+12at2s = ut + \frac{1}{2} at^2

First, we isolate the term containing aa:

sut=12at2s - ut = \frac{1}{2} at^2

Next, multiply both sides by 22 to eliminate the fraction:

2(sut)=at22(s - ut) = at^2

Now, divide by t2t^2 to solve for aa:

a=2(sut)t2a = \frac{2(s - ut)}{t^2}

This gives us the equation expressing aa in terms of ss, uu, and tt.

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