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The diagram shows a circle, centre the origin - OCR - GCSE Maths - Question 17 - 2017 - Paper 1

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The diagram shows a circle, centre the origin. (a) Write down the equation of the circle. (b) Point P has coordinates (8, –6). Show that point P lies on the circle... show full transcript

Worked Solution & Example Answer:The diagram shows a circle, centre the origin - OCR - GCSE Maths - Question 17 - 2017 - Paper 1

Step 1

Write down the equation of the circle.

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Answer

The equation of a circle with center at the origin (0, 0) and radius r is given by:

x2+y2=r2x^2 + y^2 = r^2

From the diagram, we can see the radius is 10. Thus, the equation of the circle is:

x2+y2=100x^2 + y^2 = 100

Step 2

Show that point P lies on the circle.

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Answer

To determine if point P (8, -6) lies on the circle, we will substitute x = 8 and y = -6 into the circle's equation:

  1. Calculate: 82+(6)2=64+36=1008^2 + (-6)^2 = 64 + 36 = 100

  2. Since 100=100100 = 100, point P lies on the circle.

Step 3

Find the equation of the tangent to the circle at point P.

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Answer

The gradient of the radius to point P can be calculated using the coordinates of the origin (0, 0) and point P (8, -6):

  1. Calculate the gradient of the radius: m_{radius} = rac{y_2 - y_1}{x_2 - x_1} = rac{-6 - 0}{8 - 0} = - rac{3}{4}

  2. The gradient of the tangent line is the negative reciprocal of the radius's gradient: m_{tangent} = rac{4}{3}

  3. Using the point-slope form of the equation of a line, the equation of the tangent line at point P (8, -6) is: y - (-6) = rac{4}{3}(x - 8)

  4. Rearranging the equation gives: y + 6 = rac{4}{3}x - rac{32}{3} y = rac{4}{3}x - rac{32}{3} - 6 y = rac{4}{3}x - rac{32}{3} - rac{18}{3} y = rac{4}{3}x - rac{50}{3}

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