Finley has 72 sweets - OCR - GCSE Maths - Question 15 - 2023 - Paper 1
Question 15
Finley has 72 sweets.
Finley gives
- 25% of the sweets to Alex.
- \( \frac{1}{6} \) of the sweets to Umi.
Show that Finley has \( \frac{7}{12} \) of the sweets left.
Worked Solution & Example Answer:Finley has 72 sweets - OCR - GCSE Maths - Question 15 - 2023 - Paper 1
Step 1
Calculate the sweets given to Alex
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Answer
To find the amount of sweets given to Alex, calculate 25% of 72:
25% of 72=10025×72=18
So, Finley gives 18 sweets to Alex.
Step 2
Calculate the sweets given to Umi
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Answer
Next, to find the sweets given to Umi, calculate ( \frac{1}{6} ) of 72:
61 of 72=672=12
Finley gives 12 sweets to Umi.
Step 3
Calculate the total sweets given away
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Answer
Now, add the sweets given to Alex and Umi to find the total given away:
Total given =18+12=30
Step 4
Calculate the sweets left
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Answer
Finally, subtract the total given away from the initial amount to find how many sweets are left:
Sweets left =72−30=42
To show this as a fraction of the total, calculate:
TotalSweets left=7242=127
Thus, Finley has ( \frac{7}{12} ) of the sweets left.