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3(a) Anne, Barry and Colin share a prize in the ratio 3 : 4 : 5 - OCR - GCSE Maths - Question 3 - 2019 - Paper 4

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3(a) Anne, Barry and Colin share a prize in the ratio 3 : 4 : 5. Colin gives 1/3 of his share to a charity. What fraction of the whole prize does Colin give to the ... show full transcript

Worked Solution & Example Answer:3(a) Anne, Barry and Colin share a prize in the ratio 3 : 4 : 5 - OCR - GCSE Maths - Question 3 - 2019 - Paper 4

Step 1

What fraction of the whole prize does Colin give to the charity?

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Answer

To solve this, we first need to determine Colin's share of the prize. The total parts of the prize shared by Anne, Barry, and Colin is:

3+4+5=123 + 4 + 5 = 12

Colin's share is thus:

512\frac{5}{12}

Colin gives 13\frac{1}{3} of his share to charity, which can be calculated as follows:

13×512=536\frac{1}{3} \times \frac{5}{12} = \frac{5}{36}

Thus, the fraction of the whole prize that Colin gives to the charity is:

536\frac{5}{36}.

Step 2

How much money did they share?

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Answer

Given that Freya’s share is £1600 and represents 8 parts in the ratio 5 : 7 : 8, we can find the value of one part:

The total parts are:

5+7+8=205 + 7 + 8 = 20

From Freya's share, we can determine the value of one part as follows:

Value of one part=16008=200\text{Value of one part} = \frac{1600}{8} = 200

Now, the total money shared can be calculated by multiplying the value of one part by the total number of parts:

Total money shared=20×200=4000\text{Total money shared} = 20 \times 200 = 4000.

Therefore, Delia, Edwin, and Freya shared £4000.

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