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Andrew is thinking of a number - OCR - GCSE Maths - Question 3 - 2017 - Paper 1

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Andrew is thinking of a number. - It is between 1 and 150. - It is one more than a square number. - It is three less than a cube number. - It is not a prime number.... show full transcript

Worked Solution & Example Answer:Andrew is thinking of a number - OCR - GCSE Maths - Question 3 - 2017 - Paper 1

Step 1

It is one more than a square number.

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Answer

Let the square number be represented as n2n^2. Then, Andrew's number can be expressed as x=n2+1x = n^2 + 1.

Step 2

It is three less than a cube number.

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Answer

Let the cube number be represented as m3m^3. From the earlier expression, we have x=m33x = m^3 - 3.

Step 3

Combine and solve.

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Setting both equations equal gives us: n2+1=m33n^2 + 1 = m^3 - 3 This simplifies to: m3n2=4m^3 - n^2 = 4

Step 4

Consider the range and prime condition.

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Answer

We need values of mm and nn that satisfy this equation, with 1<x<1501 < x < 150, and xx should not be a prime number. Testing integers, we find: For m=2m = 2, 812=48 - 1^2 = 4, thus x=83=5x = 8 - 3 = 5 (a prime, discard). For m=3m = 3, 2752=427 - 5^2 = 4, thus x=273=24x = 27 - 3 = 24 (not prime, valid). Verifying: it is one more than 2323 (a square) and three less than 2727 (a cube). Therefore, Andrew's number is 24.

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