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6 (a) Simplify; (i) 3a × 4 (ii) b × b × b × b (iii) c² × c⁴ (b) Factorise - OCR - GCSE Maths - Question 6 - 2023 - Paper 3

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6-(a)-Simplify;--(i)-3a-×-4--(ii)-b-×-b-×-b-×-b--(iii)-c²-×-c⁴--(b)-Factorise-OCR-GCSE Maths-Question 6-2023-Paper 3.png

6 (a) Simplify; (i) 3a × 4 (ii) b × b × b × b (iii) c² × c⁴ (b) Factorise. 9 – 6y

Worked Solution & Example Answer:6 (a) Simplify; (i) 3a × 4 (ii) b × b × b × b (iii) c² × c⁴ (b) Factorise - OCR - GCSE Maths - Question 6 - 2023 - Paper 3

Step 1

Simplify; (i) 3a × 4

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Answer

To simplify the expression, multiply the coefficients:

3a×4=12a3a × 4 = 12a

Thus, the simplified result is 12a.

Step 2

Simplify; (ii) b × b × b × b

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104 rated

Answer

This can be simplified using the exponent notation for repeated multiplication:

b×b×b×b=b4b × b × b × b = b^4

Therefore, the result is b⁴.

Step 3

Simplify; (iii) c² × c⁴

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Answer

When multiplying like bases, we add the exponents according to the rules of exponents:

c2×c4=c2+4=c6c² × c⁴ = c^{2+4} = c^6

Thus, the result is c⁶.

Step 4

Factorise. 9 – 6y

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120 rated

Answer

To factorise the expression, we can take out the common factor:

96y=3(32y)9 - 6y = 3(3 - 2y)

So, the factorised form is 3(3 - 2y).

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