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15. (c) Given the expression $$2x - 5 = 4$$, find the value of $x$ - OCR - GCSE Maths - Question 18 - 2023 - Paper 5

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15.-(c)-Given-the-expression--$$2x---5-=-4$$,-find-the-value-of-$x$-OCR-GCSE Maths-Question 18-2023-Paper 5.png

15. (c) Given the expression $$2x - 5 = 4$$, find the value of $x$. Also, determine the maximum value of the function $f(x) = x^2 - 4x + 3$.

Worked Solution & Example Answer:15. (c) Given the expression $$2x - 5 = 4$$, find the value of $x$ - OCR - GCSE Maths - Question 18 - 2023 - Paper 5

Step 1

Find the value of $x$ in the equation $2x - 5 = 4$

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Answer

To solve for xx, start by isolating xx in the equation:

  1. Add 5 to both sides: 2x5+5=4+52x - 5 + 5 = 4 + 5 2x=92x = 9

  2. Divide both sides by 2: x=92x = \frac{9}{2} Therefore, the value of xx is 4.54.5.

Step 2

Determine the maximum value of the function $f(x) = x^2 - 4x + 3$

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Answer

To find the maximum value of the quadratic function, we can use the vertex formula. The vertex form of a quadratic function gives the maximum (or minimum) point:

  1. Identify the coefficients: f(x)=ax2+bx+cf(x) = ax^2 + bx + c where a=1a = 1, b=4b = -4, and c=3c = 3.

  2. Calculate the xx-coordinate of the vertex using the formula: x=b2ax = -\frac{b}{2a} This gives: x=42×1=42=2x = -\frac{-4}{2 \times 1} = \frac{4}{2} = 2

  3. Substitute xx back into the function to find the maximum value: f(2)=224(2)+3f(2) = 2^2 - 4(2) + 3 =48+3=1= 4 - 8 + 3 = -1 Therefore, the maximum value of the function is 1-1.

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