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The diagram shows a triangle, ABC, with perpendicular height BD - OCR - GCSE Maths - Question 14 - 2023 - Paper 5

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The diagram shows a triangle, ABC, with perpendicular height BD. BC = 12 cm, angle BCD = 30° and angle BAD = 45°. Work out the length of BD. (a) ...................... show full transcript

Worked Solution & Example Answer:The diagram shows a triangle, ABC, with perpendicular height BD - OCR - GCSE Maths - Question 14 - 2023 - Paper 5

Step 1

Work out the length of BD.

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Answer

To find the length of BD, we can use trigonometric ratios.

  1. First, identify angle BDA, which is 45ext°45^ ext{°}. Since triangle ABD is a right triangle, we can apply the tangent function: tan(45ext°)=BDAD\tan(45^ ext{°}) = \frac{BD}{AD} From this, we know that AD=BDAD = BD since tan(45ext°)=1\tan(45^ ext{°}) = 1.

  2. Now, move on to triangle BCD, where we know angle BCD is 30ext°30^ ext{°} and BC = 12 cm. Using the sine function, we have: sin(30ext°)=BDBC\sin(30^ ext{°}) = \frac{BD}{BC} Thus: 12=BD12\frac{1}{2} = \frac{BD}{12} Therefore, we can rearrange it to find BD: BD=12×12=6extcm.BD = 12 \times \frac{1}{2} = 6 ext{ cm}.

So, the length of BD is 6 cm.

Step 2

Work out the exact length of AB.

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Answer

To determine the length of AB, we apply the sine rule or cosine rule in triangle ABD. Since angle BAD is 45ext°45^ ext{°} and angle BDA is also 45ext°45^ ext{°}, we can calculate:

  1. In triangle ABD, we state: AB=BDsin(30ext°)=612=12extcm.AB = \frac{BD}{\sin(30^ ext{°})} = \frac{6}{\frac{1}{2}} = 12 ext{ cm}.

Hence, the exact length of AB is 12 cm.

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