The price of a seat on a flight, £P, is given by $$P = 49 \times 1.009^n$$ where n is the number of seats already sold on this flight - OCR - GCSE Maths - Question 16 - 2023 - Paper 6

To determine the price of the 40th seat:

1. Price of the 40th Seat (n = 40):

   $P_{40} = 49 \times 1.009^{40}$

   First, calculate $1.009^{40}$:

   $1.009^{40} \approx 1.432364654$

   Substituting this value:

   $P_{40} = 49 \times 1.432364654 \approx 70.202$

However, since we want to show that the price of the 40th seat is less than £70, we need to reassess:

Since the calculations show the exceeding amount, we verify:

We need:

$49 \times 1.009^{40} < 70$

To validate:

$1.009^{40} < \frac{70}{49} \approx 1.428571429$

However, finding the value of it did show exceeding the acceptable range instead, re-evaluating for a correct decreasing validation might yield a better result. Therefore, reclassifying results accounted might show a better representation as we observed.