Mo's tyre pressure gauge shows a reading which is 12% higher than the actual pressure - OCR - GCSE Maths - Question 5 - 2017 - Paper 1

To find the actual pressure, let the actual pressure be denoted as $P$.

Since Mo's gauge shows a reading that is 12% higher than the actual pressure, we can express this as:

$38.64 = P + 0.12P$

This simplifies to:

$38.64 = 1.12P$

Now, we can solve for $P$:

$P = \frac{38.64}{1.12}$

Calculating this gives:

$P = 34.5$

Thus, the actual pressure when Mo's gauge shows 38.64 is 34.5.