This is a fair 5-sided spinner - OCR - GCSE Maths - Question 6 - 2017 - Paper 1

To find the probability that the product is a multiple of 3, we first analyze the products:

The products that are multiples of 3 from our table are:

• 3 (1,3)
• 6 (2,3 and 3,2)
• 9 (3,3)
• 12 (3,4 and 4,3)

Counting the favorable outcomes, we find a total of 6 outcomes that are multiples of 3. The total number of possible outcomes is 25 (5 scores for the first spin multiplied by 5 for the second spin).

Thus, the probability is given by: $P(multiple ext{ }of ext{ }3) = \frac{6}{25}$

To satisfy Ciara's statement (the probability that the product is negative is 0.48), we can use a certain configuration of numbers on the spinner. For example:

• 1, 1, -1, -1, -1

With these numbers, we have 2 positive and 3 negative outcomes. The product of two spins will be negative if one of the scores is positive and the other negative.

Calculating the probability:

• Total outcomes = 25 (5x5)
• Favorable outcomes (1 positive with 1 negative): 2 (positives) * 3 (negatives) = 6.
• Therefore, the probability that the product is negative is: $P(negative) = \frac{6}{25} = 0.48$