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Rashid drives his car along a road passing through two sets of traffic lights - OCR - GCSE Maths - Question 13 - 2017 - Paper 1

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Question 13

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Rashid drives his car along a road passing through two sets of traffic lights. The tree diagram shows the probabilities of the lights being red when he reaches them.... show full transcript

Worked Solution & Example Answer:Rashid drives his car along a road passing through two sets of traffic lights - OCR - GCSE Maths - Question 13 - 2017 - Paper 1

Step 1

Complete the tree diagram.

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Answer

The tree diagram is completed by filling in the probabilities for the second set of traffic lights. The probability for the first set being not red is:

egin{align*} P( ext{Not red}) &= 1 - P( ext{Red})
&= 1 - 0.6
&= 0.4 ext{For the second set:} P( ext{Not red}) &= 1 - P( ext{Red})
&= 1 - 0.7
&= 0.3

Final tree diagram probabilities are:

  • First Set: Red: 0.6, Not Red: 0.4
  • Second Set: Red: 0.7, Not Red: 0.3

Step 2

Write down the probability that the first set is not red.

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Answer

The probability that the first set is not red is:

P(extNotred)=0.4P( ext{Not red}) = 0.4.

Step 3

Given that the first set is red, write down the probability that the second set is not red.

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Answer

Given that the first set is red, the probability that the second set is not red is:

P(extNotredRed)=0.3P( ext{Not red | Red}) = 0.3.

Step 4

Work out the probability that both sets are not red.

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Answer

To find the probability that both sets are not red, we use:

P(extBothnotred)=P(extNotred)imesP(extNotred)=0.4imes0.3=0.12P( ext{Both not red}) = P( ext{Not red}) imes P( ext{Not red}) = 0.4 imes 0.3 = 0.12.

Step 5

Work out the probability that at least one set is red.

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Answer

To calculate the probability that at least one set is red, we use the complement rule:

P(extAtleastonered)=1P(extBothnotred)P( ext{At least one red}) = 1 - P( ext{Both not red})

=10.12=0.88= 1 - 0.12 = 0.88.

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