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Reuben is playing a matching game with these cards - OCR - GCSE Maths - Question 11 - 2017 - Paper 1

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Reuben is playing a matching game with these cards. He turns the cards over and shuffles them. Reuben takes a card and keeps it. He then takes a second card. If the... show full transcript

Worked Solution & Example Answer:Reuben is playing a matching game with these cards - OCR - GCSE Maths - Question 11 - 2017 - Paper 1

Step 1

Complete this tree diagram to show the probabilities for each card picked in the game.

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Answer

To complete the tree diagram, we need to calculate the probabilities for each card selection.

  1. First Card: Reuben has 4 circle cards and 5 square cards out of a total of 9 cards. Therefore:

    • Probability of picking a Circle first: ( P(Circle) = \frac{4}{9} )
    • Probability of picking a Square first: ( P(Square) = \frac{5}{9} )
  2. Second Card: Based on what he picks first:

    • If the first card is a Circle (4 cards remain), there will be 3 circles and 5 squares left:
      • Probability of picking Circle second: ( P(Circle ; | ; Circle) = \frac{3}{8} )
      • Probability of picking Square second: ( P(Square ; | ; Circle) = \frac{5}{8} )
    • If the first card is a Square (5 cards remain), there will be 4 circles and 4 squares left:
      • Probability of picking Circle second: ( P(Circle ; | ; Square) = \frac{4}{8} = \frac{1}{2} )
      • Probability of picking Square second: ( P(Square ; | ; Square) = \frac{4}{8} = \frac{1}{2} )

The completed tree diagram probabilities are:

  • First Card: Circle - Probability ( \frac{4}{9} )
    • Second Card: Circle - Probability ( \frac{3}{8} )
    • Second Card: Square - Probability ( \frac{5}{8} )
  • First Card: Square - Probability ( \frac{5}{9} )
    • Second Card: Circle - Probability ( \frac{4}{8} )
    • Second Card: Square - Probability ( \frac{4}{8} )

Step 2

What is the probability that Reuben wins the game?

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Answer

Reuben wins if he picks different cards in his two selections.

  1. If the first card is Circle and the second card is Square:

    • Probability: ( P(Circle) \times P(Square ; | ; Circle) = \frac{4}{9} \times \frac{5}{8} = \frac{20}{72} = \frac{5}{18} )
  2. If the first card is Square and the second card is Circle:

    • Probability: ( P(Square) \times P(Circle ; | ; Square) = \frac{5}{9} \times \frac{4}{8} = \frac{20}{72} = \frac{5}{18} )

To find the total probability that Reuben wins, we sum the probabilities of the two winning scenarios:

[ P(Win) = P(Circle ; first, ; Square ; second) + P(Square ; first, ; Circle ; second) ] [ P(Win) = \frac{5}{18} + \frac{5}{18} = \frac{10}{18} = \frac{5}{9} ]

Thus, the probability that Reuben wins the game is ( \frac{5}{9} ).

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