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A model railway is built using the scale 1 : 87 - OCR - GCSE Maths - Question 13 - 2017 - Paper 1

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A model railway is built using the scale 1 : 87. (a) On the model railway, the distance between the rails is 16.5mm. Calculate, in metres, the distance between the r... show full transcript

Worked Solution & Example Answer:A model railway is built using the scale 1 : 87 - OCR - GCSE Maths - Question 13 - 2017 - Paper 1

Step 1

Calculate, in metres, the distance between the rails for a full-size train.

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Answer

To find the distance for a full-size train, we first calculate the actual distance using the scale.

Given that the scale is 1 : 87, this means that 1 unit on the model represents 87 units in reality.

The distance on the model is 16.5 mm. To convert this to metres, we first convert mm to m:

16.5extmm=16.5imes103extm=0.0165extm16.5 ext{ mm} = 16.5 imes 10^{-3} ext{ m} = 0.0165 ext{ m}

Next, we multiply by the scale factor:

extDistanceforfullsizetrain=0.0165extmimes87 ext{Distance for full-size train} = 0.0165 ext{ m} imes 87 =1.4355extm= 1.4355 ext{ m}

Therefore, the distance between the rails for a full-size train is approximately 1.44 m.

Step 2

Is Trevor's calculation correct? Show how you decide.

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Answer

To determine if Trevor's calculation of 334 cm³ is correct, we can compare his figure to the known volume of the full-size train carriage, which is 220 m³.

First, we need to convert 220 m³ into cm³:

220extm3=220imes106extcm3=220000000extcm3220 ext{ m³} = 220 imes 10^6 ext{ cm³} = 220000000 ext{ cm³}

Now, to find the corresponding volume of the model train carriage using the scale of 1 : 87:

Using the relationship:

ext{Model volume} = rac{ ext{Full-size volume}}{87^3}

Calculating:

= rac{220000000}{658503} ext{ cm³} \ ext{(approx)} = 334.26 ext{ cm³} $$ Trevor's calculation of 334 cm³ can be considered accurate to 3 significant figures. Thus, Trevor's calculation is correct.

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