The diagram shows triangle OAB and points C and D - OCR - GCSE Maths - Question 16 - 2019 - Paper 4
Question 16
The diagram shows triangle OAB and points C and D.
OA = 3a and OB = 3b.
C lies on AB such that AC = 2CB.
D is such that BD = 2a + b.
Show, using vectors, that OCD ... show full transcript
Worked Solution & Example Answer:The diagram shows triangle OAB and points C and D - OCR - GCSE Maths - Question 16 - 2019 - Paper 4
Step 1
AC = 2CB
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Answer
Let the position vector of point C be represented as vector OC. Then, we can express AC in terms of the position vectors:
From the triangle, we have:
Vector AC = Vector C - Vector A
Vector C = Vector OC = OA + CB
Given that AC = 2CB, we can set up the equation:
extVectorAC=2imesextVectorCB
We can express Vector CB as:
Vector CB = Vector B - Vector C = OB - OC, where OB = 3b.
Thus, we have:
AC=OC−OA=C−A
and substituting in:
OC−OA=2(3b−OC)
Step 2
BD = 2a + b
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Answer
The position vector for point D can be expressed as:
extVectorD=extVectorB+(2a+b)
Since BD is defined as the difference in position vectors, we can write:
extVectorBD=extVectorD−extVectorB=(2a+b)
Now, we need to show that points O, C, and D are collinear. For this, we can express vectors OC and OD in terms of scalars:
extVectorOD−extVectorOC=k(extVectorOB−extVectorOA) for some scalar k.
Thus, by showing that the ratios of the components between OC and OD are equal, we can conclude that OCD forms a straight line.