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Find the coordinates of the turning point of the graph of $y = x^2 + 6x + 17.$ - OCR - GCSE Maths - Question 14 - 2021 - Paper 1

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Find the coordinates of the turning point of the graph of $y = x^2 + 6x + 17.$

Worked Solution & Example Answer:Find the coordinates of the turning point of the graph of $y = x^2 + 6x + 17.$ - OCR - GCSE Maths - Question 14 - 2021 - Paper 1

Step 1

Step 1: Identify the equation

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Answer

The given equation is a quadratic function represented as y=x2+6x+17y = x^2 + 6x + 17. This is in the standard form of a quadratic equation.

Step 2

Step 2: Complete the square

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Answer

To find the turning point, we can complete the square. Starting with the equation:

y=x2+6x+17y = x^2 + 6x + 17

We focus on the quadratic and linear parts:

y=(x2+6x)+17y = (x^2 + 6x) + 17

Next, to complete the square for x2+6xx^2 + 6x, we take half of 6, which is 3, square it to get 9, and rewrite the equation:

y=(x+3)2−9+17y = (x + 3)^2 - 9 + 17

Thus, the equation simplifies to:

y=(x+3)2+8y = (x + 3)^2 + 8

Step 3

Step 3: Identify the turning point

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Answer

From the completed square form, y=(x+3)2+8y = (x + 3)^2 + 8, we can identify the turning point. The vertex of the parabola occurs at the point where the squared term is equal to zero. Therefore, the xx-coordinate of the turning point is −3-3 and the yy-coordinate is 8.8.

Thus, the coordinates of the turning point are (−3,8).(-3, 8).

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