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Here is a right-angled triangle - OCR - GCSE Maths - Question 18 - 2018 - Paper 1

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Question 18

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Here is a right-angled triangle. 5.25 cm 18.75 cm Work out the value of x.

Worked Solution & Example Answer:Here is a right-angled triangle - OCR - GCSE Maths - Question 18 - 2018 - Paper 1

Step 1

Work out the value of x.

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Answer

To find the length of x in the right-angled triangle, we can use the Pythagorean theorem, which states that in a right triangle:

a2+b2=c2a^2 + b^2 = c^2

where cc is the length of the hypotenuse, and aa and bb are the lengths of the other two sides.

In this triangle, we can identify:

  • a=5.25 cma = 5.25 \text{ cm}
  • c=18.75 cmc = 18.75 \text{ cm}
  • b=x cmb = x \text{ cm} (the side we're trying to find)

Plugging in the known values into the Pythagorean theorem gives:

(5.25)2+x2=(18.75)2(5.25)^2 + x^2 = (18.75)^2

Calculating the squares:

27.5625+x2=351.562527.5625 + x^2 = 351.5625

Now, isolate x2x^2:

x2=351.562527.5625x^2 = 351.5625 - 27.5625 x2=324x^2 = 324

Taking the square root of both sides:

x=324x = \sqrt{324} x=18x = 18

Thus, the value of x is:

x=18 cmx = 18 \text{ cm}

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