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Asha worked out $$\frac{326.8 \times (6.94 - 3.4)}{59.4}$$ She got an answer of 19.5, correct to 3 significant figures - OCR - GCSE Maths - Question 3 - 2018 - Paper 1

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Asha-worked-out--$$\frac{326.8-\times-(6.94---3.4)}{59.4}$$--She-got-an-answer-of-19.5,-correct-to-3-significant-figures-OCR-GCSE Maths-Question 3-2018-Paper 1.png

Asha worked out $$\frac{326.8 \times (6.94 - 3.4)}{59.4}$$ She got an answer of 19.5, correct to 3 significant figures. Write each number correct to 1 significant... show full transcript

Worked Solution & Example Answer:Asha worked out $$\frac{326.8 \times (6.94 - 3.4)}{59.4}$$ She got an answer of 19.5, correct to 3 significant figures - OCR - GCSE Maths - Question 3 - 2018 - Paper 1

Step 1

Write each number correct to 1 significant figure

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Answer

For the calculations:

  • 326.8 rounds to 300
  • 6.94 rounds to 7
  • 3.4 rounds to 3
  • 59.4 rounds to 60

Now substituting these rounded values into the expression:

300×(73)60\frac{300 \times (7 - 3)}{60}

which simplifies to:

300×460=120060=20\frac{300 \times 4}{60} = \frac{1200}{60} = 20

Step 2

Is Asha's answer reasonable?

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Answer

Asha's calculated answer is 19.5 which, when rounded to 1 significant figure, is 20.

Since 20 is very close to Asha's answer of 19.5, we can conclude that Asha's estimate is reasonable.

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