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Complete this table for $y = x^2 - 5$ - OCR - GCSE Maths - Question 15 - 2017 - Paper 1

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Complete this table for $y = x^2 - 5$. $x$ | -2 | -1 | 0 | 1 | 2 | 3 | 4 $y$ | -4 | -5 | -5 | -4 | -1 | 4 | 11 (b) On the grid be... show full transcript

Worked Solution & Example Answer:Complete this table for $y = x^2 - 5$ - OCR - GCSE Maths - Question 15 - 2017 - Paper 1

Step 1

Complete this table for y = x^2 - 5

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Answer

To complete the table, we calculate the value of yy for each corresponding xx value:

  • For x=2x = -2:

    y=(2)25=45=1y = (-2)^2 - 5 = 4 - 5 = -1

  • For x=1x = -1:

    y=(1)25=15=4y = (-1)^2 - 5 = 1 - 5 = -4

  • For x=0x = 0:

    y=(0)25=05=5y = (0)^2 - 5 = 0 - 5 = -5

  • For x=1x = 1:

    y=(1)25=15=4y = (1)^2 - 5 = 1 - 5 = -4

  • For x=2x = 2:

    y=(2)25=45=1y = (2)^2 - 5 = 4 - 5 = -1

  • For x=3x = 3:

    y=(3)25=95=4y = (3)^2 - 5 = 9 - 5 = 4

  • For x=4x = 4:

    y=(4)25=165=11y = (4)^2 - 5 = 16 - 5 = 11

The completed table is:

xx-2-101234
yy-1-4-5-4-1411

Step 2

On the grid below, draw the graph of y = x^2 - 5 for the values of x from -2 to 4

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Answer

To draw the graph of y=x25y = x^2 - 5 from x=2x = -2 to x=4x = 4, plot the following points using the previously calculated values:

  • (-2, -1)
  • (-1, -4)
  • (0, -5)
  • (1, -4)
  • (2, -1)
  • (3, 4)
  • (4, 11)

Using the grid, ensure to accurately plot these points. The curve will open upwards, reflecting the nature of a parabola, and connecting these points smoothly will form the graph.

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