Here is Mario's answer to a question - OCR - GCSE Maths - Question 3 - 2018 - Paper 4

To find the value of $x$, we can use the Law of Sines as the triangle is not a right-angled triangle. According to the Law of Sines:

$\frac{x}{\sin(43^\circ)} = \frac{6}{\sin(88^\circ)}$

Rearranging for $x$, we get:

$x = \frac{6 \cdot \sin(43^\circ)}{\sin(88^\circ)}$

Calculating this:

• Calculate $\sin(43^\circ)$ and $\sin(88^\circ)$.
• Substitute these values:

$x = \frac{6 \cdot \sin(43^\circ)}{\sin(88^\circ)} \approx \frac{6 \cdot 0.681998}{0.998629} \approx 4.094$

Thus, $x \approx 4.094$ mm (to 3 decimal places).