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Sketch the graph of $y = - ext{sin} \, x$ for $0^ ext{o} < x \leq 360^ ext{o}$. - OCR - GCSE Maths - Question 16 - 2019 - Paper 6

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Question 16

Sketch-the-graph-of-$y-=---ext{sin}-\,-x$-for-$0^-ext{o}-<-x-\leq-360^-ext{o}$.-OCR-GCSE Maths-Question 16-2019-Paper 6.png

Sketch the graph of $y = - ext{sin} \, x$ for $0^ ext{o} < x \leq 360^ ext{o}$.

Worked Solution & Example Answer:Sketch the graph of $y = - ext{sin} \, x$ for $0^ ext{o} < x \leq 360^ ext{o}$. - OCR - GCSE Maths - Question 16 - 2019 - Paper 6

Step 1

Identify the Behavior of the Function

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Answer

The function y=extsinxy = - ext{sin} \, x is the reflection of the sine wave across the x-axis. The standard sine function oscillates between -1 and 1, thus y=extsinxy = - ext{sin} \, x will oscillate between -1 and 1.

Step 2

Determine Key Points

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Answer

The sine function has key points at intervals of 90exto90^ ext{o}, therefore the following key points for y=extsinxy = - ext{sin} \, x are relevant:

  • At x=0extox = 0^ ext{o}, y=extsin(0)=0y = - ext{sin}(0) = 0.
  • At x=90extox = 90^ ext{o}, y=extsin(90)=1y = - ext{sin}(90) = -1.
  • At x=180extox = 180^ ext{o}, y=extsin(180)=0y = - ext{sin}(180) = 0.
  • At x=270extox = 270^ ext{o}, y=extsin(270)=1y = - ext{sin}(270) = 1.
  • At x=360extox = 360^ ext{o}, y=extsin(360)=0y = - ext{sin}(360) = 0.

Step 3

Sketch the Graph

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Answer

To sketch the graph:

  1. Plot the key points identified above on the Cartesian plane.
  2. Connect these points with a smooth, continuous wave-like curve. Ensure the curve starts at (0,0)(0, 0), dips to (90,1)(90, -1), returns to (180,0)(180, 0), rises to (270,1)(270, 1), and ends back at (360,0)(360, 0) to complete one cycle.
  3. The approach creates a visual representation of the negative sine function across the specified interval.

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