13 (a) Sketch the graph of $y = ext{sin} \, x$ for $0^{\circ} \leq x < 360^{\circ}$ - OCR - GCSE Maths - Question 13 - 2020 - Paper 1
Question 13
13 (a) Sketch the graph of $y = ext{sin} \, x$ for $0^{\circ} \leq x < 360^{\circ}$.
(b) The graph of $y = ext{cos}(x - 30^{\circ})$ for $0^{\circ} \leq x < 360... show full transcript
Worked Solution & Example Answer:13 (a) Sketch the graph of $y = ext{sin} \, x$ for $0^{\circ} \leq x < 360^{\circ}$ - OCR - GCSE Maths - Question 13 - 2020 - Paper 1
Step 1
Sketch the graph of $y = ext{sin} \, x$ for $0^{\circ} \leq x < 360^{\circ}$
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To sketch the graph of y=extsinx, we can follow these steps:
Determine Key Points: The sine function starts at 0, reaches a maximum of 1 at 90∘, returns to 0 at 180∘, reaches a minimum of -1 at 270∘, and returns to 0 at 360∘. These key points can be calculated as follows:
sin(0∘)=0
sin(90∘)=1
sin(180∘)=0
sin(270∘)=−1
sin(360∘)=0
Plot Points: Plot the points (0,0), (90,1), (180,0), (270,-1), and (360,0) on the graph.
Draw the Curve: Connect the points with a smooth curve, forming a wave pattern that peaks at 90∘ and reaches a trough at 270∘.
Label Axes: Label the x-axis from 0 to 360∘ and y-axis from -1 to 1.
Step 2
Write down the values of $x$ where $y = \text{cos}(x - 30^{\circ})$ crosses the x-axis.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The graph of y=cos(x−30∘) crosses the x-axis when:
Determine x values: The cosine function crosses the x-axis when y=0.
Therefore, we need to solve:
cos(x−30∘)=0
Find Angles: The angles for which cosine is zero are:
x−30∘=90∘ or x−30∘=270∘
Solving gives:
x=120∘
x=300∘
Therefore, the values of x where the cosine graph crosses the x-axis are: