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The diagram shows two right-angled triangles ABD and BCD, sharing a common side BD - OCR - GCSE Maths - Question 11 - 2018 - Paper 1

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Question 11

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The diagram shows two right-angled triangles ABD and BCD, sharing a common side BD. AD = 10 cm, BC = 12 cm and angle DBC = 60°. Work out the length of AB.

Worked Solution & Example Answer:The diagram shows two right-angled triangles ABD and BCD, sharing a common side BD - OCR - GCSE Maths - Question 11 - 2018 - Paper 1

Step 1

1. Find the length of BD using triangle BCD

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Answer

In triangle BCD, we can use the cosine rule to find BD.

Using the formula: BD=BCcos(60)BD = BC \cdot \cos(60^{\circ}) Substituting the values: BD=120.5=6 cmBD = 12 \cdot 0.5 = 6 \text{ cm}

Step 2

2. Find the length of AB using triangle ABD

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Answer

In triangle ABD, we can now use the Pythagorean theorem to find AB:

The side AD = 10 cm and we have found BD = 6 cm. Therefore, we can apply: AB2+BD2=AD2AB^2 + BD^2 = AD^2 Substituting the known values: AB2+62=102AB^2 + 6^2 = 10^2 This results in: AB2+36=100AB^2 + 36 = 100 Thus: AB2=64AB^2 = 64 Taking the square root gives: AB=8 cmAB = 8 \text{ cm}

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