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A train is travelling with a velocity of 15 m/s - OCR - GCSE Maths - Question 12 - 2020 - Paper 1

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A train is travelling with a velocity of 15 m/s. It then accelerates at 0.5 m/s² for 6 seconds. Use the formula v = u + at to calculate the velocity of the train aft... show full transcript

Worked Solution & Example Answer:A train is travelling with a velocity of 15 m/s - OCR - GCSE Maths - Question 12 - 2020 - Paper 1

Step 1

Calculate the velocity after 6 seconds

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Answer

To calculate the final velocity of the train after 6 seconds, we can use the formula:

v=u+atv = u + at

where:

  • u=15 m/su = 15 \text{ m/s} (initial velocity)
  • a=0.5 m/s2a = 0.5 \text{ m/s}^2 (acceleration)
  • t=6 st = 6 \text{ s} (time)

Now substitute the values into the formula:

v=15+(0.5×6)v = 15 + (0.5 \times 6)

Calculating further: v=15+3=18 m/sv = 15 + 3 = 18 \text{ m/s}

Thus, the final velocity of the train after 6 seconds is 18 m/s.

Step 2

Rearrange the formula v = u + at to make a the subject

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Answer

To rearrange the formula to make aa the subject, we start from:

v=u+atv = u + at

First, isolate the term containing aa by subtracting uu from both sides:

vu=atv - u = at

Next, divide both sides by tt to solve for aa:

a=vuta = \frac{v - u}{t}

So, the rearranged formula is:

a=vuta = \frac{v - u}{t}

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