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Complete the table for $y = x^2 - 2x$ - OCR - GCSE Maths - Question 7 - 2017 - Paper 1

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Complete the table for $y = x^2 - 2x$. | $x$ | -1 | 0 | 1 | 2 | 3 | 4 | |-----|----|---|---|---|---|---| | $y$ | 3 | 0 | -1| 0 | 3 | 8 | Draw the graph of $y = x^... show full transcript

Worked Solution & Example Answer:Complete the table for $y = x^2 - 2x$ - OCR - GCSE Maths - Question 7 - 2017 - Paper 1

Step 1

Complete the table for $y = x^2 - 2x$

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Answer

To complete the table, we can substitute the values of xx into the equation y=x2−2xy = x^2 - 2x:

  1. For x=−1x = -1:
    y=(−1)2−2(−1)=1+2=3y = (-1)^2 - 2(-1) = 1 + 2 = 3

  2. For x=0x = 0:
    y=(0)2−2(0)=0−0=0y = (0)^2 - 2(0) = 0 - 0 = 0

  3. For x=1x = 1:
    y=(1)2−2(1)=1−2=−1y = (1)^2 - 2(1) = 1 - 2 = -1

  4. For x=2x = 2:
    y=(2)2−2(2)=4−4=0y = (2)^2 - 2(2) = 4 - 4 = 0

  5. For x=3x = 3:
    y=(3)2−2(3)=9−6=3y = (3)^2 - 2(3) = 9 - 6 = 3

  6. For x=4x = 4:
    y=(4)2−2(4)=16−8=8y = (4)^2 - 2(4) = 16 - 8 = 8

Thus, the completed table becomes:

xx-101234
yy30-1038

Step 2

Draw the graph of $y = x^2 - 2x$ for $-1 \leq x \leq 4$

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Answer

To draw the graph, plot the points from the completed table:

  • The point (−1,3)(-1, 3)
  • The point (0,0)(0, 0)
  • The point (1,−1)(1, -1)
  • The point (2,0)(2, 0)
  • The point (3,3)(3, 3)
  • The point (4,8)(4, 8)

Connect these points smoothly to form a parabolic curve, ensuring that it passes through all defined points for the given range of xx.

Step 3

Use your graph to solve $x^2 - 2x = 2$

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Answer

To solve the equation using the graph, rearrange it to the form y=0y = 0:

x2−2x−2=0x^2 - 2x - 2 = 0

Now, we need to find the points at which the graph intersects the line y=2y = 2. By observing the graph drawn in part (b), the points of intersection can be identified.

From the graph, it can be determined that the solutions for xx are approximately x≈2.9x \approx 2.9 and x≈−0.9x \approx -0.9. Therefore, the solutions to x2−2x=2x^2 - 2x = 2 are:

  • x≈2.9x \approx 2.9
  • x≈−0.9x \approx -0.9

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