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Here is a sequence - OCR - GCSE Maths - Question 16 - 2018 - Paper 5

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Question 16

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Here is a sequence. 5 5√3 15 15√3 (a) Work out the next term. (b) Find the nth term.

Worked Solution & Example Answer:Here is a sequence - OCR - GCSE Maths - Question 16 - 2018 - Paper 5

Step 1

(a) Work out the next term.

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Answer

To determine the next term in the sequence, let's examine the terms given:

  • The first term is 5.
  • The second term is 5√3.
  • The third term is 15.
  • The fourth term is 15√3.

Observing the sequence, we notice that the numbers alternate between a multiple of 5 and a multiple of √3. The pattern seems to be as follows:

  • 1st term: 5=5×15 = 5 \times 1
  • 2nd term: 53=5×35√3 = 5 \times \sqrt{3}
  • 3rd term: 15=5×315 = 5 \times 3
  • 4th term: 153=5×3315√3 = 5 \times 3 \sqrt{3}

Following the pattern, the next term (5th term) would be 5×5=255 \times 5 = 25.

Step 2

(b) Find the nth term.

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Answer

To find the nth term of the sequence, we can deduce a general formula based on the identified pattern.

The terms can be represented as follows:

  • For odd n, the terms are: 5×(n/2)5 \times (n/2) when n is odd (1st, 3rd, ...)
  • For even n, the terms are: 5×(n/2)35 \times (n/2) \sqrt{3} when n is even (2nd, 4th, ...)

Thus, we can express the nth term as:

T(n)=5×((n+12) for odd n, and (n2)3 for even n)T(n) = 5 \times \left(\left(\frac{n+1}{2}\right) \text{ for odd n, and } \left(\frac{n}{2}\right) \sqrt{3} \text{ for even n}\right)

This captures the required format for the nth term.

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